我係中一的,諗到少少野,我唔知啱唔啱。 <BAC=30 30+<ABC(90)+<ACB=180(< SUM OF TRIANGLE) <ACB=30 LINE QC and LINE OR is parallel. <BOR=90 <ORB=30 so <OBR+90+30=180(< SUM OF TRIANGLE) <QOR=90 <QOR+<OQC+<ORC+<QCR=360(ALL INTERIOR ANGLES OF A QUADRILATERAL) 90+90+30+<ORC=360 <ORC=150 TRIANGLE AOBA IS AN ISOSCELES TRIANGLE. LINE AO AND LINE OB IS THE SAME <AORCA IS A TRAPEZIUM. LINE AO = LINE RC LINE BP = LINE RC. BECAUSE TRIANGLE BOPB IS AN EQUILATERAL TRIANGLE. LINE AO = LINE OP = LINE BP = LINE BO |