[問題]S3 Maths - Deductive Geometry

oscar

Originally posted by 落雷 at 2005-4-14 22:57:
ADP≡BCQ(RHS)
∠DAP=∠CBQ
ADB≡BCA(SAS)
AC=BD
ADC≡BCD(SSS)
∠DCE=∠CDE
∠EBA=∠DAB
AEB is isoscles

*only key steps are written

[ Last edited by 落雷 on 2005-4-14 at 11:05 PM ]

哈哈！你的方法與我校另一位數學老師的方法一樣！
好野！等我仲諗左成3日...

JOHNLAM17

冇人理我o既...
我個answer長左d je...=.=

oscar

Originally posted by JOHNLAM17 at 2005-4-15 19:24:
冇人理我o既...
我個answer長左d je...=.=

如果以中三的程度去做，你的方法是太複雜...

細薯

Originally posted by 落雷 at 2005-4-14 10:57 PM:
ADP≡BCQ(RHS)
∠DAP=∠CBQ
ADB≡BCA(SAS)
AC=BD
ADC≡BCD(SSS)
∠DCE=∠CDE
∠EBA=∠DAB
AEB is isoscles

*only key steps are written

[ Last edited by 落雷 on 2005-4-14 at 11:05 PM ]

To 落雷：
prove到 red part is enough.
ADB≡BCA(SAS)
∠DBA = ∠CAB

[ Last edited by smallpotato226 on 2005-4-16 at 12:47 PM ]

JOHNLAM17

Originally posted by oscar at 2005-4-15 07:57 PM:

如果以中三的程度去做，你的方法是太複雜...

但係我基本上只係prove兩個triangle congrent.........