 圖就先放上來 1. In ΔABC, AB²+BC²=AC² (Pyth. thm.) AC=√ 6²+8² km AC=10 km 2. In ΔABC, sin∠ACB=AB/AC ∴ ∠ACB=53.13° (cor to 2 d.p.) ∴the bearing is N53.13°W 3. The Reservoir should be at point E. BE =CE =AC/2 =5 km 4.In ΔBEF, cos∠EBF=BF/BE cos∠EBF=4/5 ∴ ∠EBF=36.87° (cor to 2 d.p.) ∠CBE=90° -∠EBF =53.13° ∴the bearing is S53.13°W 很大機會錯的:hug: [ 本帖最後由 mk311111 於 31/8/2008 01:01 PM 編輯 ] |