[2a^(-2) + a^(-2)]^3 = [(2 + 1)a^(-2)]^3 = [3a^(-2)]^3 = 27a^(-6) = 27 / a^6 The answer is correct. It seems that you miscalculate and give out an extra 1/2. Then after the power of 3, it gives out 1/8. Try to find the error by checking each step. [ 本帖最後由 sapphire 於 5/10/2008 06:44 PM 編輯 ] |