(a) (2x - 3)y + xy =y(2x - 3+x)=y(3x-3)=3y(x-1) (b) (6x - 5)(x - y) - x(x - y)=(x - y)(6x - 5-x)=(x - y)(5x - 5)=5(x - y)(x - 1) (c) (2x + 3)(x - y) + (1 - x)(y - x)=(2x + 3)(x - y) - (1 - x)( x - y )=( x - y )(2x + 3-1+x)=( x - y )(3x + 2) [ 本帖最後由 mk311111 於 7/1/2009 05:52 PM 編輯 ] |