tan90∘→∞ cot90∘=1/tan90∘→0 3^0.5/tanA-2cosA=0 (3^0.5-2sinA)/tanA=0 (3^0.5-2sinA)cotA=0 3^0.5-2sinA=0 or cotA=0 A=60∘ or 90∘ u should not multiply both sides by tanA as u will miss the root 90. note that if the question has not state A lies in the 1st quad., there are 2 more roots. ===================================================== however, i think it is not good to do in this way as it contains limit. [3^(1/2)]/tanA-2cosA=0 cosA[3^(1/2)/sinA-2]=0 cosA=0 or 2sinA=3^(1/2) A=60∘ or 90∘ [ 本帖最後由 sapphire 於 9/4/2007 16:45 編輯 ] |