HKCEE A. Maths. (Circle)

小耀

Originally posted by 落雷 at 2005-3-16 08:18 PM:
C[2]-C[1]:6x+6y+F-1=0
Comparing with 6x+6y+18=0
F-1=18
F=19

Since x+y+3=0, y=-x-3
let A(a,-a-3) be an any point on PQ
Length tangent to C[1]
=√[a^2+(-a-3)^2+4a-2(-a-3)+1]
=√[a^2+a^2+6a+ ...

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